3.2.30 \(\int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx\) [130]

Optimal. Leaf size=23 \[ \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \]

[Out]

Chi(1/2*x)*sech(1/2*x)*(a+a*cosh(x))^(1/2)

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Rubi [A]
time = 0.07, antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3400, 3382} \begin {gather*} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + a*Cosh[x]]/x,x]

[Out]

Sqrt[a + a*Cosh[x]]*CoshIntegral[x/2]*Sech[x/2]

Rule 3382

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[c*f*(fz/d)
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3400

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[(2*a)^IntPart[n]
*((a + b*Sin[e + f*x])^FracPart[n]/Sin[e/2 + a*(Pi/(4*b)) + f*(x/2)]^(2*FracPart[n])), Int[(c + d*x)^m*Sin[e/2
+ a*(Pi/(4*b)) + f*(x/2)]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rubi steps

\begin {align*} \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx &=\left (\sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {x}{2}\right )}{x} \, dx\\ &=\sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 23, normalized size = 1.00 \begin {gather*} \sqrt {a (1+\cosh (x))} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a + a*Cosh[x]]/x,x]

[Out]

Sqrt[a*(1 + Cosh[x])]*CoshIntegral[x/2]*Sech[x/2]

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Maple [F]
time = 0.41, size = 0, normalized size = 0.00 \[\int \frac {\sqrt {a +a \cosh \left (x \right )}}{x}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+a*cosh(x))^(1/2)/x,x)

[Out]

int((a+a*cosh(x))^(1/2)/x,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="maxima")

[Out]

integrate(sqrt(a*cosh(x) + a)/x, x)

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {a \left (\cosh {\left (x \right )} + 1\right )}}{x}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))**(1/2)/x,x)

[Out]

Integral(sqrt(a*(cosh(x) + 1))/x, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="giac")

[Out]

integrate(sqrt(a*cosh(x) + a)/x, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {\sqrt {a+a\,\mathrm {cosh}\left (x\right )}}{x} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + a*cosh(x))^(1/2)/x,x)

[Out]

int((a + a*cosh(x))^(1/2)/x, x)

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